Python 3: Remove items at positions 1,2,4,8,16,.. from list

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0

How would I go about removing every element with index 2^x in a list? I've tried using a for loop with a variable representing x increasing by 1 in every loop but this throws the out of range error.

e.g:

remove([0,0,1,1,0,1,0,1,1])
>>>[1,0,1,0,1]

asked 1 min ago

Liam_S

8

Python 3: Remove items at positions 1,2,4,8,16,.. from list