PHP replace wildcards (%s, %d) in string with vars

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I have translate function t($var);

function t($word) {
    return $this->words[$word];
}

where $this->words is array

$this->words = array(
    'word1' => 'word',
    'word2' => 'something'
);

I am using functions as <?php echo t('word1'); ?> and output is : word

My goal is to use wildcards %s, %d, %f to replace them with variables. Example:

$this->words = array(
    'word1' => 'word',
    'word2' => 'something',
    'sentence' => 'Hello, my name is %s. I am %d years old.'
);

Then parse variables into t() function.

<?php echo t('sentence', array('Mike', 99));

So output will be: Hello, my name is Mike. I am 99 years old.

My Work so far:

function t($word, $vars = array()) {
    foreach ($vars as $key) {
        if(is_string($key)){
            $this->words[$word] = str_replace ('%s', $key, $this->words[$word]);
        }
        if(is_int($key)) {
            $this->words[$word] = str_replace ('%d', $key, $this->words[$word]);
        }
        if(is_float($key)){
            $this->words[$word] = str_replace ('%f', $key, $this->words[$word]);
        }
    }
    return $this->words[$word];
}

But this function doesn't work with more than one of each type of variable.

asked 29 secs ago

Ing. Michal Hudak

1,284