Created a php function to take in a page_id and based on the current page_id display or not display another php file

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I have made a function that take in the current page id and base on that result will ever show two .php file or just one .php file.

My question is: Have I approached this in the wright way?

<?php
function get_search_or_nav($page_id) {

    if(isset($page_id)) {

       $id = $page_id;
       $pages = array('home', 'thank-you');

       foreach($pages as $page){

          if($page==$id)
            $match = true;
       }
       if($match) {
          include("dir/file_1.php"); 
          include("dir/file_2.php"); 
       } 
       elseif (!$match) {
          include("dir/file_1.php");
       } 
   }
}
?>

The $pages variable holds the $page_id array i.e.$pages = array('home', 'thank-you');

each .php file has a $page_id i.e index.php has $page_id = "home";

The array is a list of the matching $page_id's:

$pages = array('home', 'thank-you');

The call would then be:

get_search_or_nav($page_id);

Any help or advise would be great, this is my first question here so please excuse me if i have made any mistakes...

asked 15 secs ago

BrainDead

1

Created a php function to take in a page_id and based on the current page_id display or not display another php file