if comparison from dictionary lists

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0

So I have a dictionary

alice = { "name": "Alice", "homework": [100.0, 92.0, 98.0, 100.0], "quizzes": [82.0, 83.0, 91.0], "tests": [89.0, 97.0] }

and a function that takes the average of a list

def average(numbers):
return float(sum(numbers))/len(numbers)

The problem is here. I want python, with the function get_average(), to read through a dictionary. After that I want the function to take the average of a list in the dictionary and multiply the average of that list with a specific number (grading weights with .10 for homeworks,.30 for quizzes,or.60 for test) and give the total of the weighted homeworks, quizzes, and test. I am using a if statement to check whether the list selected from the for-loop in the dictionary is homework, quizzes, or tests.

def get_average(alice): hw=0 qz=0 ts=0

for assignment in student:
    if assignment== ["homework"]:  
        hw=average(assignment)*.10
    if assignment==["quizzes"]:
        qz=average(assignment)*.30
    if assignment==["tests"]:
        ts=average(assignment)*.60

return hw+qz+ts

This only returns zero. It should be 91.15

asked 51 secs ago

fathalpert

1

if comparison from dictionary lists