Undefined offset: 1 when checking if isset in function

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$s = "text";
$exploded_s = explode('/', $s);
//$s2 = isset_or($exploded_s[1], "empty"); //This shows notice Undefined offset: 1
$s2 = isset($exploded_s[1]) ? $exploded_s[1] : "empty"; //This is ok
echo $s2;

function isset_or($var, $val){
    return isset($var) ? $var : $val;
}

Both return "empty" but the first way also shows the notice. Why?

asked 2 mins ago

Loclip

1,196

1 Answer

Vote count:

0

You get an Undefined Offset here

$s2 = isset_or($exploded_s[1], "empty");

That is because the $s had no / inside of it , so the array $exploded_s probably wont have anything inside it.

answered 10 secs ago

Shankar Damodaran

24.4k