64bits warning conversion from size_t to double

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0

I have this warning under Visual Studio

conversion form size_t to double possible loss of data

with the following code

int maFunc(double Test)
{
  return 0;
}

size_t test = 6666;
int toto = maFunc(test);

I do not understand this warning (I could use a static_cast but i would like to understand why, i understand this warning on int with possible overflow)

asked 15 secs ago

parisjohn

1

64bits warning conversion from size_t to double