sort 2 arrays simultaneously in C

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I have 2 arrays which i want to sort together e.g. 1 is a character A-Z and the other is an ID number: 1,2,3...

char arr1[3][10] = {C, B, A}; int arr2[3] = {2,1,2};

The code i have below sorts the 2nd array numerically from lowest to highest, and sorts the 1st array together/accordingly.

array that is unordered:

Charlie            2         
Bravo              1          
Aplha              2   

Bravo              1           
Charlie            2          
Aplha              2

MY QUESTION is that how can i sort arr1 alphabetically if there are duplicates in arr2. You can see below Alpha and Charlie flip as they have duplicates values in arr2, this is what i want my output to look like.

Bravo              1           
Aplha              2           
Charlie            2       

Below is my code. Does anyone know how to fix the code to do this function of sorting arr1 in alphabetical order if arr2 has duplicates.

#include <stdio.h>
#include <stdlib.h>


int cmp(const void *a, const void *b) { 
    return strcmp(a, b); 
}

void sort(long sz, char arr1[][5], int arr2[])
{
long i;
long j;
char arr1temp[5];
int arr2temp;

for(i=1; i<sz; ++i) {
    j=i;
    while(j>0 && arr2[j-1] > arr2[j]) {
        arr2temp = arr2[j-1];
        arr2[j-1] = arr2[j];
        arr2[j] = arr2temp;

        strcpy(arr1temp, arr1[j-1]);
        strcpy(arr1[j-1], arr1[j]);
        strcpy(arr1[j], arr1temp);
        j = j-1;
        }
    }


}

int main()
{
    int i,j,count;

    char arr1[3][5] = {"C", "B", "A"};
    int arr2[3] = {2,1,2};
    printf("ordered list\n");
    for (i=0;i<3;i++)
        printf("%s\t%d\n",arr1[i],arr2[i]);
    printf("unordered list\n");
    sort(3, arr1, arr2);        
    for (i=0;i<3;i++)
        printf("%s\t%d\n",arr1[i],arr2[i]);
}

Output:

unordered list
C       2
B       1
A       2

ordered list
B       1
C       2
A       2

asked 21 secs ago

user3035890

26

sort 2 arrays simultaneously in C