Initialize an array with copy

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[Example:

consider int x[3][5];

Here x is a 3 × 5 array of integers. When x appears in an expression, it is converted to a pointer to (the first of three) five-membered arrays of integers. In the expression x[i] which is equivalent to *(x+i), x is first converted to a pointer as described; then x+i is converted to the type of x , which involves multiplying i by the length of the object to which the pointer points, namely five integer objects [...]

Since the type of x is an "array of 3 arrays of 5 integers" we have that x+i too. Assume that i = 2;

What is the value of the x + i (Call him arr) elements after convertion to array of 3 arrays of 5 integers? I mean what arr[3] equals to?

asked 34 secs ago

Dmitry Fucintv

2,651

Initialize an array with copy