store string in char array assignment makes integer from pointer without a cast

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#include <stdio.h>

  int main(void){
   char c[8];
   *c = "hello";
   printf("%s\n",*c);
   return 0;
   }

I am learning pointers recently. above code gives me an error - assignment makes integer from pointer without a cast [enabled by default]. I read few post on SO about this error but was not able to fix my code. i declared c as any array of 8 char, c has address of first element. so if i do *c = "hello", it will store one char in one byte and use as many consequent bytes as needed for other characters in "hello". Please someone help me identify the issue and help me fix it. mark

asked 1 min ago

user3551094

1

store string in char array assignment makes integer from pointer without a cast