Python : __init__ asks for three arguments, yet when I call it claims it requires one argument?

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I have a client-server program I'm making, and essentially I have the Client class, which requires 3 arguments, self,host and port. However, when I attempt to create an instance of the client class I get this error.

TypeError: init() takes 1 positional argument but 3 were given

I don't understand, am I not asking for three arguments, and sending it three? What am I missing here? If you guys could help that would be amazing!

import socket
import threading 
import random

class Client(): 
    def __init__(self,host,port) : 
        self.host = host
        self.port = port 

class Server() : 
    def __init__(self) : 
        self.host = '127.0.0.1'
        self.port = 6000
        self.socket = socket.socket(socket.AF_INET,socket.SOCK_STREAM)
        self.clients = {}
        self.games = {}

    def Initiate(self) : 
        self.socket.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)
        self.socket.bind((self.host,self.port))
        self.socket.listen(6)

        print('Server has Started') 

        while True : 
           self.Scout()

    def Scout(self) : 
        self.clients[len(self.clients)] = self.socket.accept()

        print('Connection from : %s'%(str(self.clients[len(self.clients)-1][1])))

        self.clients[len(self.clients)-1] = Client(self.clients[len(self.clients)-1][1][0],self.clients[len(self.clients)-1][1][1])

    return 'New Connection'

asked 11 secs ago

user2770646

1

Python : __init__ asks for three arguments, yet when I call it claims it requires one argument?