How do I pass then use multiple variables in a php function?

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In my form I have the following code:

$id = 123;
$username = (validate_username($_POST['username']));

In a function I have:

function val_username ($data)
{
  $data = trim($data);
  if(isset($_POST['username']) && !empty($_POST['username']))
  {
    $username=strtolower(($_POST['username']));
    $query="select * from sp_users where LOWER(username)='$username'";
    if ( $id ) { $query="select * from sp_users where LOWER(username)='$username' and id != $id"; }
    $res=mysql_query($query);
    $count=mysql_num_rows($res);
    if($count > 0){ $fail = true; $msg .= "The username is already in use."; }
  }
  return ($data);
}

There is a little more to the function than the above but that is the gist of it. What I don't understand is how to pass a second variable to the function, $id and use it in the function? Rather than:

$username = (validate_username($_POST['username']));

Something like:

$username = (validate_username($_POST['username']),$id);

Then use it in the function and returning only the checked username. I can handle success/failure.

asked 41 secs ago

Catatonic

20

How do I pass then use multiple variables in a php function?