How to use loops in terms of input (in C language)?

Vote count:

0

I've been trying to get this code to work but the loop does not seem to work? I am very new to C and I sort of get confused with the syntax of this language. However my loop is not functioning like how I want it to be. I want the if and else statement to work but no matter what input (right or wrong) it always outputs "thank you".

#include <stdio.h>
#include <stdlib.h>

int confirm()
{
 char c;
 printf("Confirm (y/n): ");
 scanf("%c", &c);

 while (scanf("%c", &c))
 {
  if (c = 'Y' && 'y' && 'N' && 'n')
   {
    printf("\nthank you");
    break;
   }
   else
   {
     printf("\nInput not recognised, try again. \n");
     printf("\nConfirm (y/n): ");
     scanf("%c", &c);
   }
}
}

int main(int argc, char* agrv[])
{
confirm();
return 0;
}

it won't ask to enter another output when the output is incorrect. It just keeps ending from the if statement, thus the loop is not running? Please help.

asked 26 secs ago

George Cavalevu

4

How to use loops in terms of input (in C language)?