Return 0 when regex match is found (PHP)

Vote count:

0

I am hoping to return 0 when 2011-2016 is found in the string. For the life of me I cannot figure out a regex that will return 0 when a match is found and 1 when there is no match. Yes I could easily negate the entire statement but I was hoping to find a solution so that my code could stay tidy. Slightly OCD? yes, hope you can help, here's the PHP code. Be nice I am still learning. The code which I am hoping to change is in function passCheck variable $patternArray under the last element of the array. That is the pattern I have currently. I am hoping to return 0 when 2011-2016 is found in the string. I have looked into the looking ahead stuff and maybe its just late but I cant wrap my head around it (may not be the right approach).

<?php function digitsStr($pass)
     {
        $nums=array();
        $splt=str_split($pass);
        $count=count($splt);
        for($i=0;$count>$i;$i++)
        {
            if(preg_match("/\d/", $splt[$i])==1)
            {
                array_push($nums, $splt[$i]);
                unset($splt[$i]);
            }
        }
        $nums=array_merge($nums, $splt);
        $str=implode($nums);
        return $str;
    }
    ?>

    <?php function passCheck($string)
    {
        $string=digitsStr($string);
        $len=strlen($string);
        $msgArray=array("Must be 8-16 characters long ",
            "Cannot contain a white space ",
            "Does not contain at least 2 digits ",
            "Must contain at least 1 uppercase ",
            "Must contain at least 1 lowercase ",
            "Must contain one special charcter",
            "Cannot contain years 2011-2016");
        $patternArray=array("/^.{8,16}$/",
            "/\S{".$len."}/",
            "/\d{2,}/",
            "/[A-Z]/",
            "/[a-z]/",
            "/([!-\/]|[:-@])/",
            "/201(?![1-6])/");
        for($i=0;count($patternArray)>$i;$i++)
        {
            if(preg_match($patternArray[$i], $string)==0)
            {
                echo $msgArray[$i];
            }
        }
    }
    ?>

    <?php 
    $string="#M2010ATt123";
    passCheck($string)
    ?>

asked 28 secs ago

user3674515

1

Return 0 when regex match is found (PHP)