Swift language: How to call SecRandomCopyBytes

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From Objective-C, I could do this:

NSMutableData *data = [NSMutableData dataWithLength:length];
int result = SecRandomCopyBytes(kSecRandomDefault, length, data.mutableBytes);

When attempting this in Swift, I have the following:

let data = NSMutableData(length: Int(length))
let result = SecRandomCopyBytes(kSecRandomDefault, length, data.mutableBytes)

but I get this compiler error:

'Void' is not identical to 'UInt8'

The data.mutableBytes parameter is rejected because the types not match, but I can't figure out how to coerce the parameter (and I'm presuming it's somehow safe to do).

asked 1 min ago

Daniel

1,308

Swift language: How to call SecRandomCopyBytes