Python regex: replace everything up to, and starting from Nth element

Vote count:

0

I am using this function to warp a series of characters (text) in accordance with lineLength. How would I go about replacing every "#" before the split by "&", and every "#" after the split by "=" ?

def warpbar(text, lineLength):
    if len(text) <= lineLength:
        return text
    else:
        return text[:lineLength] + '\n' + warpbar(text[lineLength:], lineLength)

What I have:

>> text = "##########"
>> warpbar(text, 5)
#####
#####

What I want:

>> text = "##########"
>> warpbar(text, 5)
&&&&&
=====

asked 45 secs ago

octosquidopus

314

Python regex: replace everything up to, and starting from Nth element