repeating a string using a multiplier vs range()

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The following is the question I'm presented:

Given a string and a non-negative int n, return a larger string that is n copies of the original string.

string_times('Hi', 2) → 'HiHi'

string_times('Hi', 3) → 'HiHiHi'

string_times('Hi', 1) → 'Hi'

my solution for this is:

def string_times(str, n):

  if str and n >= 0:
   return str*n

the result came back as:

Expected    Run     
string_times('Hi', 2) → 'HiHi'          
string_times('Hi', 3) → 'HiHiHi'      
string_times('Hi', 1) → 'Hi'     
string_times('Hi', 0) → ''          
string_times('Hi', 5) → 'HiHiHiHiHi'            
string_times('Oh Boy!', 2) → 'Oh Boy!Oh Boy!'           
string_times('x', 4) → 'xxxx'   

string_times('', 4) → ''    None    X     <-- issue 

string_times('code', 2) → 'codecode'      
string_times('code', 3) → 'codecodecode'    

From what I can see, I'm missing the "null" part of the equation.

The solution given is the following:

def string_times(str, n):
  result = ""
  for i in range(n):  # range(n) is [0, 1, 2, .... n-1]
    result = result + str  # could use += here
  return result

My question is, in my solution does the fact that nothing*4 give nothing?

Also, can you please explain how using the built in range() function would be a more elegant solution?

Thanks in advance

asked 33 secs ago

renegade.py

8

repeating a string using a multiplier vs range()