bash printf + echo string

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So I'm trying to print a string as a argument to a program in the terminal. However, my command doesn't seem to match the string, which I need. The string I need to print is:

aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa$'\x14\x84\x04\x08'

My command:

`printf 'a%.0s' {1..76}; echo "$'\x14\x84\x04\x08'"`

Am I just making a stupid mistake?

asked 3 mins ago

Niels Sønderbæk

351

1 Answer

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0

Try like this,

~$ printf %100s |tr " " "a"; echo "$'\x14\x84\x04\x08'"
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa$'\x14\x84\x04\x08'

answered 13 secs ago

Adem Öztaş

3,021