local and global syntaxerror python

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Why does the Function def openFehBgQ(): not like the 2 instructions marked Comments 1 & 2:

Comment 1 tries to update the fehCurrent, which is declared global, but produces the following error:

      SyntaxError: name 'fehCurrent' is local and global ;

Comment 2 does not work at all although timeKill is remembered for the time.sleep Function.

#!/usr/bin/env python
# -*- coding: utf-8 -*-
import glob, subprocess, time, os

def globalVariables():
    global fehCurrent # Title (str) of current 'Child' window
    global fehNew # Title (str) of new 'Child' window
    global fehWindow # Data (array) for current 'Child' window
    global timeKill
    global timeZero


# Data (array) for current 'Child' window
fehBg = ['fehBg', '-g', '%ux%u+%u+%u' % (320, 240,  
    50,50), '-x', 'Media/Bg.jpg']
fehCurrent = 'fehq1'    # Title (str) of current 'Child' window

def openFehBgQ():
    if fehCurrent != fehNew:
        subprocess.Popen(fehWindow)
        time.sleep(timeKill)
        os.popen('%s%s' % ('pkill ', fehCurrent))
        # fehCurrent = fehNew    # See Comment 1
        timeElapsed = 0
        # timeZero = time.time()    # See Comment 2

fehNew = "fehBg"
fehWindow = fehBg
openFehBgQ() 
print "1_", fehCurrent
fehCurrent = fehNew
print "2_", fehCurrent
timeZero = time.time()

asked 2 mins ago

walter1957

1

local and global syntaxerror python