When Click on Hyperlinks in JavaFX ,a relevant URL should open in browser

Vote count:

0

I am developing an application in which I have some links added to the Listview and these links will keep on adding at runtime on some condition.So what I can't find is a way to how to open a url when clicking on a particular link.

This is the code for adding links into list view

    if(counter==1)
                {
                    Task task2 = new Task<Void>() {
                          @Override
                          public Void call() throws Exception {

                              Platform.runLater(new Runnable() {
                                public void run() {
                                     link=new Hyperlink(val);
                                    link.setStyle("-fx-border-style: none;");
                                    items.add(link);
                                    listview.setItems(items);



                                }
                              });


                            return null;

                          }
                        };
                        Thread th = new Thread(task2);
                        th.setDaemon(true);
                        th.start(); 
                        Thread.sleep(1000);


                }

I know I need to use something like this to open a url in browser when click on link

 getHostServices().showDocument(textField.getText()); 

but I don't know how to listen/track the click event for different links

asked 1 min ago

Anish Sharma

1